Tuesday, July 28, 2009

A company has three machinesA,B, C used in the production of bolts. A can produce 1000 bolts in 2 hours, B in?

A company has three machinesA,B, C used in the production of bolts. A can produce 1000 bolts in 2 hours, B in 2.5 and C in 6 hours. If A and B worked for 1 hour and then B and C finished the job, how long did it take to produce 1000 bolts?

A company has three machinesA,B, C used in the production of bolts. A can produce 1000 bolts in 2 hours, B in?
Use Rate x Time = Work and find the rate for each:





A: _rate_ x 2 = 1000, so the rate = 500 per hour


B: _rate_ x 2.5 = 1000, so the rate = 400 per hour


C: _rate_ x 6 = 1000, so the rate = 166 1/3 per hour





A %26amp; B working for 1 hour = (400+500) = 900.


then you need B %26amp; C to finish the remaining 100, so (400+166 1/3) x _time_ = 100. Time= .177 hours.





So 1 hour + .177 hours = 1.177 hours, which is approximately 1 hour 10 minutes and 36 seconds.





I'm not sure what this is for, but C's time of 1000 in 6 hours seems a little wierd because it forces us to work in decimals, which is not so common for rate problems. Good luck.
Reply:Let t+1 be the time required to produce 1000 bolts.


(1/2 + 1/2.5) + (1/2.5 + 1/6) t = 1


t = 3/17


t + 1 = 20/17 = 1.1765 hours
Reply:(1/2 + 1/2.5) + (1/2.5 + 1/6) t = 1


t = 3/17


t + 1 = 20/17 = 1.1765 hours
Reply:Should be the same exact output if you use the same materials and dimensions and the machine settings are the same as machine A
Reply:18 mins

chrysanthemum

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